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Crystal Load Capacitance

Signal & Timing

Load capacitors for a crystal's specified CL, and the frequency error of the pair you fit.

Inputs

From the crystal datasheet; 8, 10, 12, 18 and 20 pF are common
Pins, pads and traces to ground; typically 2–5 pF
Hz
16 MHz
ppm
Equivalent circuit
From the datasheet; 3–30 fF for AT-cut, 2–3 fF for a 32 kHz tuning fork
From the datasheet; 1–7 pF

Results

1 passed · 1 to check
Load capacitors, each C1=C2
18pF
Pass

Checked: load error ≤ your 20 ppm budget. Rounding 18 pF to the nearest E24 value leaves +0.0 ppm, with 3 pF of stray.

Actual load capacitance CL

25 % is stray

12pF
Frequency error 

+0 Hz at 16 MHz

+0.0ppm
Trim sensitivity
All results (1)
Series capacitance of the pair 

without the stray

9pF
error against the specified CL

Accuracy

Verified against

2 independent cases. See the working.

This is a design aid. The engineer remains responsible for the design and for checking the standard itself.

Parameter sweep

Vary one input over a range and see the answer and verdict at each step, as a table and a curve.Pro

Worst-case corners

Put a tolerance on each input and get the worst-case band around the answer.Pro

Parts that track move together.Inputs in the same group move together, like the parts of a matched network. Leave independent parts ungrouped: that is the safe choice.

Circuit

The principle

A crystal is calibrated to run at its nominal frequency with a specific load capacitance CL across its terminals. In a Pierce oscillator, as in most microcontrollers, that load is two capacitors to ground plus the stray from pins and traces. Get the pair wrong and the crystal runs at a steady offset.

What the crystal sees
CL=C1C2C1+C2+CsC_L = \frac{C_1 C_2}{C_1 + C_2} + C_s
C1 and C2 are in series across the crystal; the stray adds in parallel.
Equal pair for a given C_L
C1=C2=2 (CL−Cs)C_1 = C_2 = 2\,(C_L - C_s)
Load resonance
fL=fs(1+Cm2 (C0+CL))f_L = f_s\left(1 + \frac{C_m}{2\,(C_0 + C_L)}\right)
The crystal runs above its series resonance fs by an amount set by the load. Cm and C0 are on the datasheet.
Error from a wrong load
Δff=Cm2(1C0+CL′−1C0+CL)\frac{\Delta f}{f} = \frac{C_m}{2}\left(\frac{1}{C_0 + C_L^{\prime}} - \frac{1}{C_0 + C_L}\right)
CL is the specified load, CL′ what your board presents. More load, lower frequency.
Trim sensitivity
S=Cm2 (C0+CL)2S = \frac{C_m}{2\,(C_0 + C_L)^{2}}
Frequency shift per unit of load capacitance. A small CL and C0 make a crystal easy to pull, and easy to get wrong.
  • CLC_Lload capacitance the crystal is specified for
  • CsC_sstray capacitance of pins, pads and traces, to ground
  • C1,C2C_1, C_2the two load capacitors, crystal terminal to ground
  • CmC_mmotional capacitance of the crystal
  • C0C_0shunt capacitance of the crystal
  • fsf_sseries resonance
More detail

Estimating the stray

Each oscillator pin adds a few picofarads, and a trace over a ground plane adds roughly 1 pF per centimetre. Two to five picofarads in total is usual on a compact layout. The trim sensitivity shows what each unmeasured picofarad costs in ppm.

Measure, then trim. On the first boards, measure the frequency with a counter (or a timer output derived from it) and adjust the pair. 22 pF capacitors on a 12 pF crystal is a common mistake: it shows up as a clock that loses seconds a day, or a UART that works with only some hosts.

Not covered here

  • Gain margin. Whether the oscillator can start the crystal at this load is a separate check: the negative-resistance test in the vendor's application note. Larger load capacitors need more gain and slow the start-up.
  • Drive level. The power in the crystal must stay within its rating; a series resistor on the output side is the usual control.
  • Temperature and ageing. Both add to the load error. The budget you enter is the share for load error alone.

32.768 kHz crystals

Tuning-fork crystals are less sensitive per picofarad, but their budget is tighter: 20 ppm is 1.7 s per day. Low-CL parts (6–7 pF) are common, so the stray is a large share of the total.

12 pF crystal, 3 pF stray
Each capacitor should be 2 × (12 − 3) = 18 pF, an E24 value. The crystal sees 9 + 3 = 12 pF and runs on frequency.
The same crystal with a 22 pF pair
The crystal sees 11 + 3 = 14 pF, 2 pF high. With C_m = 15 fF and C_0 = 3 pF the error is −59 ppm: a 16 MHz clock 940 Hz low, or an RTC that loses 5 s per day.
References: STMicroelectronics AN2867, Oscillator design guide for STM8 and STM32 microcontrollers (load capacitors and gain margin). Microchip AN826, Crystal Oscillator Basics and Crystal Selection. IEC 60444-1 (equivalent-circuit parameters). Related: RC / RL Filter & Time Constant, for the low-pass formed by the series resistor and C2.

Engine version ⁨1.26.4⁩